Question

19. When a force is applied on a particle of mass 200 g its
velocity changes from 20 m/s to 30 m/s in 0.2 s.
What is the acceleration of the particle? Calculate also
the magnitude of force.
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Answer 1

Answer:

Explanation:

mass = 200g = 0.2 KG

u = 20m/s

v = 30m/s

a = v-u/t

 = 30-20/0.2 = 50m/s

  force = ma = 50×0.2 =10N

 

Answer 2

Answer:

The answer is 50ms^-2 and 10N