Question

19. Which of the following is slightly soluble in water ?
B) Ca(OH)2
C) Mg(OH)
A) Be(OH)2
D) KOH​

Answer 1

Explanation:

When we consider the term solubility, we also have to also consider the fact of - like dissolves like. Usually, polar solutes are highly soluble in polar solvent. Water being a highly polar solvent can dissolve a polar solute like potassium hydroxide. The polarity of KOH arises due to the charge separation between potassium metal cation and hydroxide anion.

Therefore, it is evident that KOH is soluble in water

Answer 2

Answer:

Correct answer is D)KOH

Explanation:

KOH is hygroscopic and highly soluble in water. The aqueous solution is strongly alkaline and is called potassium hydroxide (KOH) solution. Dissolution in water is highly exothermic due to the exothermic reaction of hydrate formation.

Potassium hydroxide is a strong alkali and completely dissociates into potassium ions (K+) and hydroxide ions (OH-) in water. When potassium hydroxide is added to water, a violent reaction occurs because heat is generated when dissolved in water.

In addition, we can write the equation as

KOH + H2O ——————-> K+(aq) + OH-(aq)

Since water is polar, these ions are dissolved by H2O.

So the answer is KOH.

How are 0.5 m KOH and 0.5M KOH different from each other?

https://brainly.in/question/19271854

Write the name of compound KOH and find the moleculer?

https://brainly.in/question/43490265

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