Question

194. 6) CH2=CH-CH 2 -CH=CH2
(ii) CH2 =CH-CH==CH-CH3
(iii) CH3 -CH=CH-CH=CH-CH3
The numbers of possible geometric isomers for the above compounds respectively are:
(a) 0,2,4
(b) 2, 2,4
(c) 0,3,3
(d) 0, 2, 3
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Answer 1

Answer:

The complexes [Pt(NH 3 ) 2Cl 2 ] and [Pt(NH 3 ) 2Cl 4] show geometrical isomerism. They exist in the form of cis and trans isomers. However, they do not show optical isomerism.

The complex [Pt(en) 3 ] 4+

shows optical isomerism. It exists in the form of d and l isomers. It does not show geometrical isomerism.

The complex [Pt(en)

2 Cl 2 ] shows two geometrical isomers, cis and trans. The cis isomer is optically active and exists in d and l forms. The trans isomer is optically inactive.