Question

–195×(–53)+(–195)×(23)​

Answer 1

Step-by-step explanation:

Assumption

PQRS is parallelogram

Diagonal = 20 cm (QS)

\textbf{\underline{Two\;adjacent\;sides:-}}

Twoadjacentsides:-

PQ = 51 cm

PS = 37 cm

Now,

PS = 37 cm

PS = b = 37 cm

QS = c = 20 cm

Hence,

\tt{arrow s=\dfrac{a+b+c}{2}}arrows=

2

a+b+c

\tt{arrow s=\dfrac{51+37+20}{2}}arrows=

2

51+37+20

\tt{arrow s=\dfrac{108}{2}}arrows=

2

108

s = 54 cm

Therefore

{\boxed{\sf\:{Area\;of\;parallelogram=2\times area\;of\; \triangle PQS}}}

Areaofparallelogram=2×areaof△PQS

\tt{arrow 2\times\sqrt{s(s-a)(s-b)(s-c)}}arrow2×

s(s−a)(s−b)(s−c)

\tt{arrow 2\times\sqrt{54(54-51)(54-37)(54-20)}}arrow2×

54(54−51)(54−37)(54−20)

\tt{arrow 2\times\sqrt{54\times 3\times 17\times 34}}arrow2×

54×3×17×34

\tt{arrow 2\times\sqrt{9\times 3\times 2\times 3\times 17\times 2\times 17}}arrow2×

9×3×2×3×17×2×17

\tt{arrow 2\times\sqrt{3^2\times 3^2\times 2^2\times 17^2}}arrow2×

3

2

×3

2

×2

2

×17

2

= 2 × 3 × 3 × 2 × 17 cm²

= 36 × 17 cm²

= 612 cm²

Answer 2

Answer:

= (-195)×(-53)+(-195)×(23)

= (-195) [-53+23]

= (-195)× (30)

=(-5850)

Answer = -5850

I hope that it will help you

thanx