Question

195 men working 10 hours a day can finish a job in 20 days. how many men are employed to finish the job in 15 days. if they work 13 hours a day?​

Answer 1

Answer:

the men and number of working hours then the constant proportnality k=195*20*10... equation(1)

let the men required is equal to x

now the x*15*13.... equation(2)

now equate the equation

195*20*10=x*13*15

x=195*20*10/13*15

x=200

Answer 2

$\sf\small\underline\green{Given:-}$

$\sf{\implies Case\:_{(1)}\:work\: finished}$

$\sf{\implies No\:of\:men=195}$

$\sf{\implies No\:of\:days=20}$

$\sf{\implies work\:done\:by\:man\:_{(each\:days)}=10\: hours}$

$\sf{\implies Case\:_{(2)}\:work\: finished}$

$\sf{\implies No\:of\:men=m}$

$\sf{\implies No\:of\:days=15}$

$\sf{\implies work\:done\:by\:man\:_{(each\:days)}=13\: hours}$

$\sf\small\underline\green{To\: Find:-}$

$\sf{\implies No\:of\:men\:_{(as\:per\:case\:_{(2)}}=?}$

$\sf\small\underline\green{Solution:-}$

To calculate the number of men as per the question ,at first we have to set up equation with the help of given clue in the question. In question, given that 195 men working 10 hours a day can finish a job in 20 days. how many men are employed to finish the job in 15 days. if they work 13 hours a day?

$\tt{\implies work\:finished\:_{(Case\:_{(1)})}=work\: finished\:_{(Case\:_{(2)})}}$

$\tt{\implies M\:_{(1)}\times\:D\:_{(1)}\times\:T\:_{(1)}=M\:_{(2)}\times\:D\:_{(2)}\times\:T\:_{(2)}}$

$\tt{\implies 195\times\:20\times\:10=M\:_{(2)}\times\:15\times\:13}$

$\tt{\implies 15\times\:20\times\:10=M\:_{(2)}\times\:15}$

$\tt{\implies 20\times\:10=M\:_{(2)}}$

$\tt{\implies M\:_{(2)}=200}$

$\sf\large{Hence,}$

$\sf{\implies No\:of\:men\:_{(as\:per\:case\:_{(2)}}=200}$