Question

19समलांब चौकोन ABCD मध्ये बाजू AB 11 बाजू PQ 11 बाजू DC , AP= 15, PD= 12, QC = 14 तर BQ= .... वकती ?​

Answer 1

Given:

समलांब चौकोन ABCD

AB || बाजू PQ || बाजू DC

AP= 15

PD= 12

QC = 14

BQ=?

$\begin{array}{l}\frac{\mathrm{AP}}{\mathrm{PD}}=\frac{\mathrm{BQ}}{\mathrm{QC}} \\\\\frac{15}{12}=\frac{\mathrm{BQ}}{14}\end{array}$

$\therefore \mathrm{BQ}=\frac{15 \times 14}{12}\\\\BQ=\frac{15\times7}{6} \\\\BQ=\frac{105}{6}\\\\BQ=17.5$

Hence the value of BQ is 17.5