19x+13y=15 and 13x+19y=55,then x-y=? Give the answer with briefly
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19x+13y=15......(1)
13x+19y=55.....(2)
subtracting equation 2 from 1
=19x+13y-(13x+19y)=15-55
=6x-6y=-40
=6(x-y)=-40
so x-y=-40/6=-6.666
13x+19y=55.....(2)
subtracting equation 2 from 1
=19x+13y-(13x+19y)=15-55
=6x-6y=-40
=6(x-y)=-40
so x-y=-40/6=-6.666
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