Question

19x-3y=17,3x+5y=11 by substitution, cross multiplication & elimation method

Answer 1

pahale gand de. ........

Answer 2

19x-3y=17...........(1)*3

3x+5y=11.............(2)*19

57x-9y=51

57x+95y=209

- - - (Sign change)

.…......................

0-86y=-158

86y=158

y=158/86

y= 79/43

put in eq(1)

19x-3(79/43)=17

19x=17+237/43

19x=(731+237)/43

19x=968/43

x=968/43*19

x=968/817