19x"'y +38x"y"+19xy'''
factories by algebraic expression
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Answer:
19xy • (2y19 + 1)
Explanation:
Changes made to your input should not affect the solution:
"y1" was replaced by "y^1".
19xy + (((2•19y19) • x) • y)
Pull out like factors :
38xy20 + 19xy = 19xy • (2y19 + 1)
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