Question

1a^3/7-2a^3/√3+4a-7 is a polynomial

Answer 1

Since x3+6∗x2>=0x3+6∗x2>=0

Then, x2(x+6)>=0x2(x+6)>=0

i.e (x−0)2(x−(−6))>=0(x−0)2(x−(−6))>=0

This implies that\(x>=-6\)

Hence, x=-2 is a valid root, and sum of all roots should bex=3+(−2)=1x=3+(−2)=1

Please let me know where I am going wrong.