Question

%1a abc is isosceles with ab = ac = 7.5 cm and bc = 9 cm (fig 11.26). the height ad from a to bc, is 6 cm. find the area of %1aabc. what will be the height from c to ab i.e., ce?

Answer 1

Answer:

Step-by-step explanation

We know that  

Area of triangle = 1/2 x base x height

Now,

When base(BC) = 9 cm and height(AD) = 6 cm  

Then, the area is equal to

1/2  x 9 x 6 = 27 \ cm^2

Now,  

When base(AB) = 7.5 cm and height(CE) = h , area remain same  

Therefore,

27= 1/2 x 7.5 x CE

CE = 54/7.5 = 7.2 cm  

Therefore, value of CE is  7.2 cm  and area is equal to 27^2

hope this help you

Answer 2

Answer:

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Step-by-step explanation:

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × BC × AD

= 1/2 × 9 × 6

= 27 cm²

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × AB × CE

27 cm² = 1/ 2 × 7. 5 × CE

CE = 7.2 CM