1a) Expand :-(2 √3-5√2)
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By using Binomial Theorem, the expression (2/ x – x/2)5 can be expanded as. (2/x– x/2)5 ... Hence or otherwise evaluate (√2 + 1)6 + (√2 – 1)6 ... nCr-2 / nCr-1 = 1/3 and nCr-1 / nCr = 3/ 5.
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