1b.
6. A car travels first 30 km with a uniform speed of
60 km h-1 and then next 30 km with a uniform speed
of 40 km h-1. Calculate : (i) the total time of journey,
(ii) the average speed of the car.
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Answer:-
Given:-
- Case¹ : Distance travelled= 30 km (s₁)
Speed = 60 km/h (v₁)
- Case² : Distance travelled= 30 km (s₂)
Speed = 40 km/h (v₂)
To Find:-
- Total time of the journey.
- Avg. speed of the car.
_____________...
➽ 1. Total time taken (t):-
Time taken = Time taken in case¹ + Time taken in case²
Case¹:- (t₁)
t = s/v
➠ t = 30 km/(60 km/h)
➠ t = ½ h
Case ²:- (t₂)
t = s/v
➠ t = 30km/(40 km/h)
➠ t = ¾ h
∴ Total (t) = (t₁) + (t₂)
➠ t = (½ + ¾) h
➠ t = 5/4 h (Add the frac. by taking LCM 4)
➠ t = 1.25 h ...(Ans. 1)
➽ 2. Avg. speed of the car:-
We know,
➤ Avg. speed = Total distance/Total time taken
∴ Avg. speed = (30 km + 30 km)/(1.25 h)
➠ vₐᵥ = 60 km / 1.25 h
➠ vₐᵥ = 48 km/h ...(Ans. 2)
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