Question

1cm
A cardboard is in the form of a square of side 4 cm. Four quadrants
at the vertices of the cardboard of radius 1 cm and a circle of
diameter 2 cm is cut off. Find the remaining area of the cardboard.​

Answer 1

Answer:

$\frac{68}{7} {cm}^{2}$

Step-by-step explanation:

Given that,

Side of square = 4cm

Radius of circle = 1cm

Area of remaining portion = Area of sq. - 2(Area of circle)

${4}^{2} - 2 \times \frac{22}{7} \times {1}^{2} \: \\ \\ 16 - \frac{44}{7}$

$\frac{122 - 44}{7 \: } \: = \frac{68}{7}$