Question

1cm3 of H2 gas contains number of atoms at S.T.P

Answer 1

Solution:

➡ Given:

✏ Volume of $\rm{H_2}$ gas = $\rm{1\:cm^{3}}$

➡ To Find:

✏ No. of atoms at S.T.P

➡ Conversation:

✏ $\rm \: 1 \: cm^{3} = 1ml$

➡ Concept:

✏ 22400 ml of any gas at S.T.P contains $6.022 \times\: {10}^{23}$ atoms.

➡ Calculation:

$\mapsto \rm \: no.of \: atoms = \frac{1}{22400} \times 6.022 \times {10}^{23} \\ \\ \mapsto \: \underline{ \boxed{ \bold{ \rm{ \orange{no.of \: atoms = 2.69 \times {10}^{19}}}}}}$

➡ Additional information:

✏ 1 mol of gas occupies 22.4 L volume at S.T.P

✏ 1 mol of gas has mass equal to molecular weight.

✏ 1 mol of gas contains no.of atoms equal to Avegrado's number.