.1d + .25(d + 8) = 41
Answers
Answer:
Changes made to your input should not affect the solution:
(1): "t2" was replaced by "t^2". 1 more similar replacement(s).
(2): "4.1" was replaced by "(41/10)".
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
d*o*t^1*d+d*o*t^25*(d+8)-((41/10))=0
STEP
1
:
41
Simplify ——
10
Equation at the end of step
1
:
41
(((do•(t1))•d)+((do•(t25))•(d+8)))-—— = 0
10
STEP
2
:
Equation at the end of step 2
41
(((do•(t1))•d)+dot25•(d+8))-—— = 0
10
STEP
3
:
Rewriting the whole as an Equivalent Fraction
3.1 Subtracting a fraction from a whole
Rewrite the whole as a fraction using 10 as the denominator :
d2ot25 + d2ot + 8dot25 (d2ot25 + d2ot + 8dot25) • 10
d2ot25 + d2ot + 8dot25 = —————————————————————— = —————————————————————————————
1 10
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
STEP
4
:
Pulling out like terms
4.1 Pull out like factors :
d2ot25 + d2ot + 8dot25 = dot • (dt24 + d + 8t24)
Trying to factor a multi variable polynomial :
4.2 Factoring dt24 + d + 8t24
Try to factor this multi-variable trinomial using trial and error
Factorization fails
Adding fractions that have a common denominator :
4.3 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
dot • (dt24+d+8t24) • 10 - (41) 10d2ot25 + 10d2ot + 80dot25 - 41
——————————————————————————————— = ————————————————————————————————
10 10
Checking for a perfect cube :
4.4 10d2ot25 + 10d2ot + 80dot25 - 41 is not a perfect cube
Equation at the end of step
4
:
10d2ot25 + 10d2ot + 80dot25 - 41
———————————————————————————————— = 0
10
STEP
5
:
When a fraction equals zero
5.1 When a fraction equals zero ...
Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.
Here's how:
10d2ot25+10d2ot+80dot25-41
—————————————————————————— • 10 = 0 • 10
10
Now, on the left hand side, the 10 cancels out the denominator, while, on the right hand side, zero times anything is still zero.
The equation now takes the shape :
10d2ot25+10d2ot+80dot25-41 = 0
Solving a Single Variable Equation:
5.2 Solve 10d2ot25+10d2ot+80dot25-41 = 0
In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.
We shall not handle this type of equations at this time.
Answer:
.1d + .25(d + 8) = 41
Step-by-step explanation:
.1d + .25(d + 8) = 41
.1d +.25d+2 =41
.26d = 39
d=41÷ .26
= 4100 ÷ 26= 157.69