Question

1f a-b= 6 and ab = 16, find a^2+b^2​

Answer 1

Answer:

a-b= 6

ab= 16

(a-b)² = 6²

a²+b²-2ab = 36

a²+b²= 36+2×16

a²+b²=36+32

a²+b²= 68

Answer 2

Answer:

a - b = 6

a = b + 6

$a {}^{2} + b {}^{2} = (b + 6 ) {}^{2} + b {}^{2}$

$b {}^{2} + 36 + 12b \: + b {}^{2} = 0$

$2b {}^{2} + 12b \: + 36 = 0$

$b {}^{2} + 6b + 18 = 0$