1f
a/b + b/a = -1
(a,b not equal to 0)
find value of a3-b3
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Answer:
a/b + b/a= -1
Take Lcm
(a2+b2)/ab= -1
a2+b2= -ab--------Equation 1
a3-b3=(a – b) (a2 + ab + b2 )
From equation 1,
a3-b3=(a-b) ( -ab+ab )
a3-b3=(a-b) (0)
Therefore, a3-b3=0
Hope this helps you.......
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