Question

1f (x+1/x)=8, find the value of
(x^2+1/x^2) ​

Answer 1

Answer:

64

Step-by-step explanation:

given:-

$( \frac{x + 1}{x} ) = 8$

ATQ:

$( \frac{x^{2} + 1}{ {x}^{2} } ) = { (\frac{ x + 1 }{x}) }^{2}$

$= {8}^{2} \: \: {since \: ( \frac{x + 1}{x} ) = 8}$

$= ( \frac{x + 1}{x})^{2} = 64$

$( \frac{ {x}^{2} + 1}{ {x}^{2} } ) = 64$

hope it helps :)