Question

1g of mg is burnt with 0.56g of oxygen in a clossed vessel which reactant is left in excess and how much

Answer 1

$2Mg+O_{2}$⇒$MgO$
So 48g $Mg$ react with 32g $O_{2}$
Hence 1g $Mg$ react with $\frac{32}{48}=0.33$g $O_{2}[\tex] We are given [tex]0.56$g $O_{2}$ so $0.56-0.33=0.23$g $O_{2}$ will remain there.