Question

1g of Mg When completely burnt in presence of O2 , 1.66g of MgO is formed Calculate the amount of MgO formed when 6g of Mg is burned completely in presence of O2

Answer 1

hey mate

Answer:

The equation is as follows:

2Mg + O2  ------>  2MgO

(s)      (g)                (s)

Therefore 2 moles of Mg require 1 mole of O2 to produce 2 moles of MgO.

Calculate actual moles.

moles= mass/ molar mass

Mg=    1/24  = 0.041667

O2=   0.56/32 = 0.0175

MgO=

Mole ratio of Mg: O2   = 2:1

find mass of Mg that reacts:

that means 2 mole of Mg reacts with 1 moles of O2

If 1 = 2 

Then 0.0175 = 0.0175 x 2

                    =0.035 moles of magnesium

mass of magnesium that reacts:

mass= moles x molar mass

       = 24 x 0.035

        

             0.84 g

That means that of the 1 gram of magnesium that reacts only 0.84 grams is used

Therefore magnesium is in excess and by 0.16

mark as brainliest answer please

Answer 2

1g of Mg=1.66 g of MgO

6g of Mg=(1.66 * 6)g of MgO

              =9.96g of MgO(Ans)