1g sample of chalk is completely neutralized by 100 ml of 0.04 HCl solution .Find the (wt/wt) °/• of caco3 sample.
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Explanation:
First of all write balanced chemical equation which is
CaCO3 + 2 HCl >> CaCl2 + H2O +CO2 (since chalk is chemically CaCO3)
One can learn from above equation
HCl = 1/2 CaCO3
Or 1000 mL 1N HCl = 50g of CaCO3 ( = 1/2 Ca+C+ 3O =1/2( 40+12+4)
1000 mL 1N HCl = 50 g
100 mL 0.04 N HCl
= 50 × 0.04 × 100/1000
= 0.2 g
so it is clear that 1 g sample actually contains 0.2 g of CaCO3 i.e. 20% .
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