Question

1gm equivalent mixture of co3 of two bivalent metals require 15ml of .5n hcl solution for complete neutralisation. If 1 metal is ca what is the atomic weight of other metal

Answer 1

Step 1:

Weight of $K_2CO_3=ag$

Weight of $Li_2CO_3=bg$

$a+b=0.5$------(1)

For reaction

Meq.of $K_2CO_3$+Meq of $Li_2CO_3$=Meq of HCl

$\large\frac{a\times 1000}{138/2}+\frac{b\times 1000}{74/2}$$=30\times 0.25$

$74a+138b=38.295$------(2)

Step 2:

By equation (1) & (2)

$a=0.48g$

$b=0.02g$

$\%$ of $K_2CO_3=\large\frac{0.48}{0.5}$$\times 100$

$\Rightarrow 96\%$

$\%$ of $Li_2CO_3=\large\frac{0.02}{0.5}$$\times 100$

$\Rightarrow 4\%$

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