Question

1gm mixture of nacl and nano3 is dissolved in water and treated with excess agno3 solution 1.43 g of ppt is formed. find percentage composition of nacl.​

Answer 1

Answer:

58.5

Explanation:

Since 143.5g of AgCl is produced from =58.5 g of NaCl

Since 143.5g of AgCl is produced from =58.5 g of NaClso, 1.435 g of AgCl is formed by = 0.585 g of NaCl

Since 143.5g of AgCl is produced from =58.5 g of NaClso, 1.435 g of AgCl is formed by = 0.585 g of NaCl% of NaCl =0.585 x100 = 58.5%

Answer 2

Explanation:

NaCl  +  KCl  +  AgNO3  --->  AgCl  +  NaNO3  +  KNO3

1.854 g AgCl is produced, 1.854 g * 1 mol / 143.32 g = 0.013 mol AgCl produced

0.013 mol AgCl * 1 mol Cl- / 1 mol AgCl = 0.013 mol Cl-

All 0.013 mol chloride ion in AgCl came from NaCl and KCl, that means the total number