Question

1gm water convertd into vapour at 100°c then amount of heat required

Answer 1

Assuming that the water is at 100C, then conversion to steam at 100C requires 2257kJ/kg, so in this case of 1kg, it’s 2257kJ.

If you have to heat the water from xC to 100C first, then we use the formula

E = m•Cp•ΔT

Where E is the heat energy required, m is the mass, Cp is the heat capacity (for water, 4.184kJ/kg-K), and ΔT is the temperature change.

In this case, we get E = 1•4.184•(100 – x)

This is added to the 2257kJ/kg.