Question

1gram NaOH is dissolved in 1/4dm cube of water .The molarity of solution is?

Answer 1

Explanation:

molarity=no. of moles of solute/volume of solvent

molarity=1÷40/.025

.1

Answer 2

Given:

Mass of solute (NaOH) = 1 g

Mass of solvent = $\frac{1}{4}$ $dm^3$

To find:

Molarity = ?

Formula to be used:

1. Number of moles = $\frac{Given mass}{Molar mass}$
2. Molarity = $\frac{Number of moles}{Volumes in Litres}$

Calculation:

As solute is given as NaOH, the number of moles present in it must be calculated. The formula used is

Number of moles = $\frac{Given mass}{Molar mass} =$ $\frac{1}{40} = 0.025$ moles

As the volume is given in $dm^3$ , it must be converted into L,

∴ $\frac{1}{4} dm^3$ = 0.25 L

Thus substituting the given values in the following formula, it gives the molarity of the solution

Molarity = $\frac{Number of moles}{Volumes in Liters}$ = $\frac{0.025}{0.25}$ = 0.1

Conclusion:

Thus the molarity of 1gram NaOH is dissolved in 1/4dm cube of water is calculated as 0.1 M.

Learn more about Molarity

The resultant molarity of solution made by mixing 600 ml of 2 M NaOH solution and 400 ml of 3M NaOH solution is

(1) 1 M

(2) 1.2 M

(3)2.4 M

(4) 3.6 M​

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