Question

1if one of the zeroes of the Polinomial p(x)= 2x^2-8x-m is 5/2 find m and the other zero

Answer 1

Hiii friend,


Given :- 5/2 is one zero of the given polynomial.



P(X) => 2X²-8X-M


P(5/2) => 2 × (5/2)² - 8 × 5/2 - M



=> 2 × 25/4 - 20 /1 - M = 0



=> 25/2 - 20/1 - M = 0


=> 25 - 40 - 2M = 0 × 2


=> -15 - 2M = 0


=> 2M = -15


=> M = -15/2



HOPE IT WILL HELP YOU....... :-)

Answer 2

Solution:-

given by equetion:-

$p(x) = 2 {x}^{2} - 8x - m \\ the \: zeroes \: are \: \frac{5}{2} \\ 2 \times \frac{5}{2} \times \frac{5}{2} - 8 \times \frac{5}{2} - m = 0 \\ \frac{25}{2} - 20 - m = 0 \\ - m = \frac{40 - 25}{2} \\ m = - \frac{15}{2} \\ the \: eqtion \: is = 2 {x}^{2} - 8x + \frac{15}{2} = 0 \\ \alpha = \frac{5}{2} \\ \beta = \frac{ - b}{a} - \frac{5}{2} \\ \beta = \frac{8}{2} - \frac{5}{2} \\ \beta = \frac{3}{2 } \\ the \: secound \: zeroes \: is \: \frac{3}{2}$