Question

1kg mass is suspended from a spring which is now stretched by 1cm if it is allowed to oscillate then its period will be

Answer 1

Given:

1kg mass is suspended from a spring which is now stretched by 1cm.

To find:

If it is allowed to oscillate then its period will be

Solution:

From given, we have,

1kg mass is suspended from a spring which is now stretched by 1cm.

We use the time period formula,

T = 2π √(m/k)

where, k = spring constant.

k = W/x = 1kg/1cm = 10N/0.01m = 1000 N/m

substituting the value of spring constant in time period equation, we get,

T = 2π √(1/1000)

T = 2 × 3.14 × (1/1000)

T = 0.1985 s

∴ The  period of oscillation will be 0.1985 sec.