Question

1L of a gas at 27 degree celsius heated till both pressure and volume are tripled. Find the new temperature

Answer 1

Answer:

2427°C or 2700 K

Explanation:

pv = nRT

$\frac{p1v1}{p2v2} = \frac{t1}{t2}$

t2 = 9*t1 (t1= 273+ 27 K)

t2 = 9*300 K = 2700 K or 2427°C