1L of a gas at constant and 20 oC is heated until its volume doubles. Find its new
temperature. [313 oC]
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Answer:
Answer is 2637K
Explanation:
Apply the formula,
PV = nRT
P1V1/P2V2 = T1/T2 [n, R is constant]
Let, P1= P, V1= V
As given - P2= 3P, V2=3V, T1= 20°C/293K
T2= ?
PV/3P×3V= 293/T2
1/9= 293/T2
T2= 293×9
T2= 2637K
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