1L of hydrocarbon at1270c and 1atm presure weighs 2.8g.It contains 10.5g of carbon per gram of hydrogen and its molecular formula will be
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Answer:
PV=nRT=
M
w
RT
or 1=
M
2.8
×0.0821×400
or M=91.95≈92
Let the formula be C
a
H
b
.
So 12a+b=92
b
12a
=10.5(given)
11.5b=92
or b=8
∴ a=7
Therefore, the formula is C
7
H
8
.
molar mass = 12*7+1*8 = 92gm/mole
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