Chemistry, asked by Rt2005FromKT, 2 days ago

1M 1L Aqueous Solution of HCl on evaporation volume of solution reduces to 600mL and concentration charges to 0.5M. Then, find the amount of HCl left from our Beaker.

Answers

Answered by psubhashini21
0

Answer:

0.685

Explanation:

The original of 0.5N HCl solution of 1 litre had 18.225 gm of HCl

Initially 18.225gm of HCl was dissolved in 1 liter of silution

After heating , mass of HCl dissolved in the reduced 600mL of solution was found to be (18.225−3.25)gm=14.975 gm

Hence

Normality of new solution=

Volume of solution in litre

Equivalent weight of HCl mass

N=

1000mL per litre

600mL

Equivalent weight of HCl

14.497

N=

0.6 litre

36.45

14.497

N=

0.6 litre

0.3977 Meq

N=0.685

Answered by qwmagpies
0

Given: 1M 1L Aqueous Solution of HCl on evaporation volume of solution reduces to 600mL and concentration charges to 0.5M.

To find: We have to find the amount of HCl left in a beaker.

Solution:

The total concentration of HCl solution is 1M.

On evaporation, only water will evaporate and the HCl will be left behind.

So, the concentration of HCl is 0.5M.

The initial volume of the aqueous solution of HCl is 1000ml.

on evaporation volume of solution reduces to 600mL.

So, the volume of HCl is 600ml.

This mass of HCl left will be-

600×.5=300

The amount of HCl left from our Beaker is 300 grams.

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