Question

1M 1L Aqueous Solution of HCl on evaporation volume of solution reduces to 600mL and concentration charges to 0.5M. Then, find the amount of HCl left from our Beaker.
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Answer 1

Answer:

1 L – 1 N HCl = 36.5 g 1L – N/2 HCl = 18.25 g Wt. of HCl lost = 3.25 g Wt. of HCl left = 15.00 g Vol. of sol. left = 600 ml. Normality = (15/ 36.5) ´ 1000/ 600 = 0.685 NRead more on Sarthaks.com - https://www.sarthaks.com/414924/one-litre-solution-heated-beaker-was-observed-that-when-the-volume-solution-reduced-600ml

Answer 2

Given: 1M 1L Aqueous Solution of HCl on evaporation volume of solution reduces to 600mL and concentration charges to 0.5M.

To find: We have to find the amount of HCl left in a beaker.

Solution:

The total concentration of HCl solution is 1M.

On evaporation, only water will evaporate and the HCl will be left behind.

So, the concentration of HCl is 0.5M.

The initial volume of the aqueous solution of HCl is 1000ml.

on evaporation volume of solution reduces to 600mL.

So, the volume of HCl is 600ml.

This mass of HCl left will be-

$600 \times .5 = 300$

The amount of HCl left from our Beaker is 300 grams.