Question

1m h2so4 solution is diluted to 0.01m h2so4 hence its molar conductivity will be

Answer 1

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It vl be decreased

Answer 2

Answer:

The molar conductance of 0.01M H₂SO₄ solution will be 100 times of molar conductance of 1M of H₂SO₄  solution.

Explanation:

Initial concentration of the sulphuric acid solution C₁ = 1M

We know that the molar conductivity of a solution is the conductance produced by all the ions produced from one mole of electrolyte in 'C' concentration solution.

$\lambda_{m}=\frac{(\kappa )*1000 }{C_{m}}$

$\lambda_{1} =\frac{\kappa *1000}{1M}$

$\lambda_{1}=1000\kappa$

After the dilution, the final concentration of the solution is C₂.

Consider that molar conductance of the final solution is $\lambda_{2}$,

$\lambda_{2}=\frac{\kappa*1000}{C_{2}}$

$\lambda_{2}=\frac{\kappa*1000}{0.01M}$

$\lambda_{2}=100*(1000\kappa)$

$\lambda_{2}=100\lambda_{1}$

Therefore, the molar conductivity of the H₂SO₄ solution after dilution will be 100 times of initial molar conductance of sulphuric acid solution.