Question

1M of glucose solution has a freezing point of -1.86 degree celsius in 10 ml of 1M glucose is mixed with 30 ml of 3M glucose that the resulting solution will have the freezing point of

Answer 1

Difference in freezing point = Freezing constant x vant hoff factor x Molarity

0 - freezing point of solution = -1.86 x 1 x 2.5

Freezing point of solution = 4.65

Answer 2

Explanation:

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