Question

1Meena tested the solubility of two different substances at different temperatures and collected the data as given below. [Results are given in the following table as grams of substance dissolved in 100 grams of water to form a saturated solution] Sr.No Substance dissolved in grams 293 K 313 K 333 K 1 Ammonium chloride 37 g 41 g 55 g 2 Potassium chloride 35 g 40 g 46 g Find the amount of ammonium chloride that will separate out when its saturated solution (1m) in water at 333 K is cooled to 293 K.

Answer 1

Answer:

18 g

Explanation:

At 333 K, the saturated solution contains 55 g of ammonium chloride. However, after cooling to 293 K, only 37 g of ammonium chloride can be dissolved. The ammonium chloride that can no longer be dissolved will separate out.

55 - 37 = 18g