Question

❇️1mole of an ideal monoatomic gas at 27degree. celcious expands adiabatically against a constant external pressure of 1atm from a volume of 5dm. square to 15dm. square calculate 1)q 2)w 3) U........❇️if you don't know then plz stay away from hear it's my humble request friends❇️ ╭∩╮(-_-)╭∩╮❇️​

Answer 1

Answer:

1. q = 0

2.w = 690 calorie (approx)

3. u = - 690

Explanation:

In adiabatic process heat exchange is zero

so that w = - u

w =uRTln(V2/V1)

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