1mole of ethyl alcohol and 1 mole of acetic acid are mixed. At equilibrium 0.666 mole of ester is present. The value of equilibrium constant is
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Now according to the equation, it is clear that 0·667 mole of acetic acid combines with a 0· 667 mole of ethyl alcohol to form a 0·667 mole of ethyl acetate and a 0·667 mole of water
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