Question

1o
(a) 32
8. If a + b + c = 6 and a2 + b2 c2 = 38. then what is the value of a/b2 + c) + b(c2 + a) +
c(a2 + b2) + 3abe?
of a + b + c = 6 R a + b + c = 38 ut alb? + 2) + bc + a) + ca? b) + 3abc z PTT SIRI
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Answer 1

Step-by-step explanation:

Given  If a + b + c = 6 and a2 + b2 c2 = 38. then what is the value of  a^3 + b^3 + c^3 – 3abc

• Given a + b + c = 6
• Squaring both sides we get
• (a + b + c)^2 = 6^
• So a^2 + b^2 + c^2 + 2(ab + bc + ca) = 36
•          38 + 2 (ab + bc + ca) = 36
•         2(ab + bc + ca) = - 2
• Or ab + bc + ca = - 1
• We know that a^3 + b^3 + c^3 – 3abc = (a + b + c)(a^2 + b^2 + c^2 – ab – bc – ca)
•                                                               =  6 (38 – (-1))
•                                                               = 6 x 39
•                                                              = 234  

Reference link will be

https://brainly.in/question/5958601