1o) In a right triangle ABC, right angled at C if angle a=30 degree and ac =√3 cm find AB and
BC
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AB+BC=AC
or, AB+BC = √3 ------> (i)
or, AB=√3-BC
in equ (i) AB+BC = √3
or, √3-BC+BC=√3
or, -BC+BC=√3-√3
or, -(BC+BC)= -(√3 + √3 )
or, 2BC = 2√3
or, BC = 2√3 / 2
or, BC = √3
in equ (i) AB+BC = √3
or, AB + √3 = √3
or, AB = √3 - √3
or, - AB = - (√3 + √3)
or, AB = 2√3
therefore, AC=√3cm.
BC=√3cm.
AB=2√3cm.
therefore, two sides are equal means it is a isosceles triangle.
Step-by-step explanation:
ABC is right angle triangle
{A=30degree, AC=√3} Given
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