Question

1P
6. The sum of the squares of
two consecutive odd numbers
is 394. find the numbers.
0
13 & 14​

Answer 1

Answer:

Step-by-step explanation:

let one number be (2n-1), then the next consecutive odd number will be (2n+1)

(2n-1)^2 + (2n+1)^2 = 394

4n^2 +1 -4n +4n^2 +1+4n = 394

8n^2 +2 = 394

8n^2 = 392

n^2 = 49

n = 7

The two consecutive numbers are :

(2n-1) = 14-1 = 13

(2n+1) = 14+1= 15

your answer is 13 and 15.

hope this helped..

Answer 2

Step-by-step explanation:

Let the first number be x

second number be x+2

x²+(x+2)²=394

$x {}^{2} + x {}^{2} + 4x + 4 = 394 \\ 2x {}^{2} + 4x = 390 \\ 2(x {}^{2} + 2x) = 390 \\ x {}^{2} + 2x = 195 \\ x(x + 2) = 195 \\ x + 2 = \frac{195}{x} \\ x = \frac{195}{x + 2} \\ \\ so \: the \: 2numbrs \: are \: 13and15$

HOPE this HELPS you BETTER

plz mark me as brainliest......