Question

1st question pls answer

Answer 1

${x}^{2} + {y}^{2} - 6x + 5y - 7 = 0 \\ g = - 3 \: and \: h = \frac{5}{2} \\centre \: of \: circle = ( - g \: \: \: \: - h) = ( 3 \: \: \: - \frac{5}{2} ) \\ c = - 7 \\ centre \: of \: circle \: is \: midpoint \: of \: diameter \: \\ let( \: x \: \: \: y) \: is \: coordinate \: of \: other \: end \\ 3 = \frac{x - 1}{2} \\ 6 = x - 1 \\ x = 7 \\ \frac{ - 5}{2} = \frac{y + 3}{2} \\ - 5 = y + 3 \\ y = - 8$