Question

1st question pls its urgent

Answer 1

Step-by-step explanation:

In ∆POQ

<OPQ = <OQP = 30°

[ Since in ∆ POQ is isosceles , OP = OQ, Radius of the circle]

Now,

<OPQ + <OQP + <POQ = 180° [Sum of all angles of a triangle]

=> 30° + 30° + <POQ = 180°

=> < POQ = 180° - 60°

=> <POQ = 120°

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Again,

In ∆OQR,

<ORQ = <OQR = 57°

[ Since in ∆ OQR is isosceles , OR = OQ, Radius of the circle]

Now,

<ORQ + <OQR + <ROQ = 180° [Sum of all angles of a triangle]

=> 57° + 57° + <ROQ = 180°

=> < ROQ = 180° - 114°

=> <ROQ = 66°

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Now,

<POR = <POQ - <ROQ

= 120° - 66°

= 54°

Therefore, <POR = 54°

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