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Given V= 4x^2 ...... (i)
Since Electric Field =-dV/dx
so ,differentiating (i)
-dV/dx = -8x
Now at point (1,0,2)
dV/dx=-8 (negative )
Hence The electric field is 8m along negative x-axis
Since Electric Field =-dV/dx
so ,differentiating (i)
-dV/dx = -8x
Now at point (1,0,2)
dV/dx=-8 (negative )
Hence The electric field is 8m along negative x-axis
shailendra123:
sir negative X dorection
yes u r right
negative
ya i forgot negative sign
Answered by
1
electric field is along only x direcyion
E = - Dv/ Dx
= -8x
hence E P along (1,0,2) is
-8*1 = -8 v/ m along X direction
E = - Dv/ Dx
= -8x
hence E P along (1,0,2) is
-8*1 = -8 v/ m along X direction
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