Question

1th
5
of a rod was painted black.
2rd
part of the total rod was
coloured white. The part of the
rod left without colour was
3​

Answer 1

Given : 1/5 of the rod was painted black

2/3 of rod was painted white

To Find : The part of  rod left without colour

Solution:

Let say Total Rod Length = 15L

Painted black = (1/5)15L  = 3L

Painted White = (2/3)15L = 10L

Remaining Part = 15L - 3L - 10L = 2L

The part of the rod left without colour  = 2L/15L

= 2/15

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Answer 2

✮ Question Given :

• 1/5 of a rod was painted black. 2/3 part of the total rod was coloured white. The part of the rod left without colour was ?

✮ Required Solution :

✫ Values Given to us :

• ⇒ 1/5 of a rod was painted black.

• ⇒ 2/3 part of the total rod was coloured white

✮ According to Question :

✫ Fact :

• ⇒ Any value in total is equal to 1.

✫ 1st Black Painted Part :-

• ⇒ Part of rod that was painted black

• ⇒ (1/5) part of 1 = 1 × (1/5) = (1/5) part

✫ 2nd White Painted Part :-

• ⇒ Part of rod that was painted white

• ⇒ (2/3) part of 1 = 1 × (2/3) = (2/3) part

✫ Total Part Painted of Rod :

• ⇒ Black Part + White Part Painted

• ⇒ (1/5) + (2/3)

• ⇒ (3 + 5*2)/15

• ⇒ (3 + 10) / 15 = (13/15) part

✫ Part left Without Colour :

• ⇒ 1 - 13/15 part

• ⇒ 2/15 ( Part left Without Colour)

⇒ ✩ 2/15 Part of Rod ✩

•The part of rod left without colour was 2/15

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