Question

1The value of x² +2y² + 3xy at x=2 y=-1 is​

Answer 1

Answer:

0

Step-by-step explanation:

Given:- x=2

y=(-1)

=> x²+y²+xy

=> (2)²+2(-1)²+3(2)(-1)

=> 4+2-6

=> 6-6

=> 0

Answer 2

Answer: 0

Step-by-step explanation:

Given: x^2 + 2y^2 +3xy

x=2 , y=-1

Then,

2²+(2×(-1)²)+(3×2×-1)

=4+2+(-6)

=6-6

=0