Question

1upon 2 x +3 square​

Answer 1

Answer:

= $\frac{1}{4x^2+12x+9}$

Step-by-step explanation:

$\frac{1}{2x+3} ^{2}$

= $\frac{1}{2x+3}$ * $\frac{1}{2x+3}$

= $\frac{1}{(2x+3)(2x+3)}$

= $\frac{1}{2x(2x+3) + 3(2x+3)}$

= $\frac{1}{4x^2+6x + 6x + 9}$

= $\frac{1}{4x^2+12x+9}$

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