Question

1upon 3 (x+7) = 1+1upon 5 (3x- 2) solve the following linear equation​

Answer 1

Step-by-step explanation:

$\frac{1}{3(x + 7)} = 1 + \frac{1}{5(3x - 2)} \\ \frac{1}{3x + 21} = 1 + \frac{1}{15x - 10} \\ \frac{1}{3x + 21} = \frac{15x - 10 + 1}{15x - 10} \\ \frac{1}{3x + 21} = \frac{15x - 9}{15x - 10} \\ 15x - 10 = 3x(15x - 9) + 21(15x - 9) \\ 15x - 10 = 45 {x}^{2} - 27x + 315x - 189 \\ 15x - 10 = 45 {x}^{2} + 288x - 189 \\ 45 {x}^{2} + 288x - 189 - 15x + 10 = 0 \\ 45 {x}^{2} + 273x - 179 = 0 \\ \\ \\ \\ mark \: brainliest$