Math, asked by gautam157, 1 year ago

1upon (root 2-roo t 3)

Answers

Answered by Anonymous
2

 \frac{1}{ \sqrt{2}  -  \sqrt{3} }  \\  \frac{1}{ \sqrt{2}  -  \sqrt{3} }  \times  \frac{ \sqrt{2}  +  \sqrt{3} }{ \sqrt{2}  +  \sqrt{3} } \\  \frac{ \sqrt{2}   +  \sqrt{3} }{ { \sqrt{2} }^{2}  -  { \sqrt{3} }^{2} }   \\   \frac{ \sqrt{2}  +  \sqrt{3} }{2 - 3}  \\  \frac{ \sqrt{2}  +  \sqrt{3} }{ - 1}  \\  -  \sqrt{2}  -  \sqrt{3}

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Answered by abhi569
4

 \frac{1}{ \sqrt{2}  -  \sqrt{3} }


By rationalization,

 \frac{1}{ \sqrt{2} -  \sqrt{3}  }  \times  \frac{ \sqrt{2}  +  \sqrt{3} }{ \sqrt{2}  + \sqrt{3}  }


 \frac{ \sqrt{2} +  \sqrt{3}  }{( \sqrt{2})^{2}   - ( \sqrt{3})^{2} }


 \frac{ \sqrt{2} +  \sqrt{3}  }{2 - 3}


 \frac{ \sqrt{2} +  \sqrt{3}  }{ - 1}


 \frac{  - 1(\sqrt{2} +  \sqrt{3})  }{1}

 -  \sqrt{2}  -  \sqrt{3}



I hope this will help you



-by ABHAY


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