Question

1upon3 (x+1) -1upon2 (x-1) = 5upon6 (x+1)

Answer 1

1/ 3(x+1) - 1/2(x-1) = 5 / 6(x+1)

In LHS, taking LCM, we get

=> (2x - 2 - 3x - 3)/6(x+1)(x-1) = 5 / 6(x+1)

=> ( - x - 5) / (x-1) = 5

=> (-x - 5) = 5x - 5

=> - x - 5 = 5x - 5

=> 6x = 0

=> x = 0